Boolean algebra simplification examples and solutions
Example 1: Simplify the Boolean
expression
Solution
Example 2: Find
the complement of the boolean expression given by
Solution
a)
Using De Morgan’s theorem
b)
Let Y be the complement of
Applying De Morgan’s theorem
Example 3: Proof that the following algebra (boolean expression) is equal
Solution
Example 4: Simplify the following Boolean expressions
Solution
a)
b)
Example 5: Proof of the Dual of Distributive Law
Which states that (x + y.z) = (x + y).(x + z)
Solution
Using the RHS
